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Catalase and capillaries

\(2\ H_2O_2 \rightarrow O_2 + 2 \ H_2O \)

We know

For \(O_{2}\) :

For \(H_{2}O\) :

–> We can neglect the volume occupied by \(H_2O\)

So now we have the following stoechiometry : \(2\ H_2O_2 \approx O_2\)

So \(n_{H_2O_2} \approx \frac{n_{O_2}}{2}\)

Putting everything together

\(catalitic \ activity (mole.s^{-1}) = speed (s^{-1}) * \frac{6.4}{2} \times 10^{-3}\)

Calculator of catalitic activity

Speed in capillary (cm/s)



Result

mol/s